4y^2-19y+41=0

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Solution for 4y^2-19y+41=0 equation:


Simplifying
4y2 + -19y + 41 = 0

Reorder the terms:
41 + -19y + 4y2 = 0

Solving
41 + -19y + 4y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
4 the coefficient of the squared term: 

Divide each side by '4'.
10.25 + -4.75y + y2 = 0

Move the constant term to the right:

Add '-10.25' to each side of the equation.
10.25 + -4.75y + -10.25 + y2 = 0 + -10.25

Reorder the terms:
10.25 + -10.25 + -4.75y + y2 = 0 + -10.25

Combine like terms: 10.25 + -10.25 = 0.00
0.00 + -4.75y + y2 = 0 + -10.25
-4.75y + y2 = 0 + -10.25

Combine like terms: 0 + -10.25 = -10.25
-4.75y + y2 = -10.25

The y term is -4.75y.  Take half its coefficient (-2.375).
Square it (5.640625) and add it to both sides.

Add '5.640625' to each side of the equation.
-4.75y + 5.640625 + y2 = -10.25 + 5.640625

Reorder the terms:
5.640625 + -4.75y + y2 = -10.25 + 5.640625

Combine like terms: -10.25 + 5.640625 = -4.609375
5.640625 + -4.75y + y2 = -4.609375

Factor a perfect square on the left side:
(y + -2.375)(y + -2.375) = -4.609375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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